problema clasa a 5 a

[slym36]

aflati numerele de forma abc ,stiind ca impartindpe abc la bc obtinem catul 6 si restul 5

[alex05ok]

abc=bc*6+5
a00=5bc+5
a00=5(bc+1)
20a=10b+c+1

a=1, 20=10b+c+1, b=1, c=9
a=2, 40=10b+c+1, b=3, c=9
a=3, 60=10b+c+1, b=5, c=9
a=4, 80=10b+c+1, b=7, c=9
a=5, 100=10b+c+1, b=9, c=9

nr sunt: 119, 239, 359, 479, 599.