Va rog daca puteti sa ma ajutati la una dintre limitele va multumesc anticipat
3 sau 4
Limita serii maclaurin
Desvoltari in serie in jurul lui 0
ln(1+X)=X-X^2/2+X^3/3-X^4/4+.....PENTRU X^2<1
sinx=x-x^2/3!+x^5/5!-.......
cosx=1-x^2/2!+x^4/4!-.....
e^x=+1+x/1!+x^2/2!+x^3/3!+......>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>................................................................
Lim(x->0)[(ln(1+2x)-sin(2x)+2x^2)/x^3]=lim(x->0)[(2x-4x^2/2+8x^3/3)-(2x-8x^3/3!)+2x^2
=lim(x->0)[(2x-2x)-(2x^2-2x^2)+(8x^3/3+8x^3/6)]/x^3=24/6=4
asa sa incercis faci si tu la celelalte exercitii. SUCCES
ln(1+X)=X-X^2/2+X^3/3-X^4/4+.....PENTRU X^2<1
sinx=x-x^2/3!+x^5/5!-.......
cosx=1-x^2/2!+x^4/4!-.....
e^x=+1+x/1!+x^2/2!+x^3/3!+......>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>................................................................
Lim(x->0)[(ln(1+2x)-sin(2x)+2x^2)/x^3]=lim(x->0)[(2x-4x^2/2+8x^3/3)-(2x-8x^3/3!)+2x^2
=lim(x->0)[(2x-2x)-(2x^2-2x^2)+(8x^3/3+8x^3/6)]/x^3=24/6=4
asa sa incercis faci si tu la celelalte exercitii. SUCCES