Va rog frumos sa ma ajutati la aceasta ecuatie.
(x+1)(x+2)=72 . Stiu cat trebuie sa dea, dar nu stiu cum sa arat asta.
Va multumesc mult
Ecuatie clasa a V-a: (x+1)(x+2)=72
(x+1)*(x+2)=72
Avem produsul a doua nr.(x+1)*(x+2) = 72 ,adica :
.................. => Primul factor si al doilea factor
=>1).72=1*72 => x+1=1=>x=0 si x+2=72 =>x=70;
.....2).72=2*36 => x+1=2=>x=1 si x+2=36 =>x=34;
.....3).72=3*24 => x+1=3=>x=2 si x+2=24 =>x=22;
.....4).72=4*18 => x+1=4=>x=3 si x+2=18 =>x=16;
.....5).72=6*12 => x+1=6=>x=5 si x+2=12 =>x=10;
.....6).72=8*9 => x+1=8 =>x=7 si x+2=9 =>x=7 ;
.................. => Primul factor si al doilea factor
=>1).72=1*72 => x+1=1=>x=0 si x+2=72 =>x=70;
.....2).72=2*36 => x+1=2=>x=1 si x+2=36 =>x=34;
.....3).72=3*24 => x+1=3=>x=2 si x+2=24 =>x=22;
.....4).72=4*18 => x+1=4=>x=3 si x+2=18 =>x=16;
.....5).72=6*12 => x+1=6=>x=5 si x+2=12 =>x=10;
.....6).72=8*9 => x+1=8 =>x=7 si x+2=9 =>x=7 ;
ecuatie cls a V-a
Multumesc mult pt. raspuns